10x^2+13x-23=0

Solution for 10x^2+13x-23=0 equation:

10x^2+13x-23=0

a = 10; b = 13; c = -23;
Δ = b2-4ac
Δ = 132-4·10·(-23)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-33}{2*10}=\frac{-46}{20}
=-2+3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+33}{2*10}=\frac{20}{20}
=1
$